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-0.4x^2-3x+1=0
a = -0.4; b = -3; c = +1;
Δ = b2-4ac
Δ = -32-4·(-0.4)·1
Δ = 10.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{10.6}}{2*-0.4}=\frac{3-\sqrt{10.6}}{-0.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{10.6}}{2*-0.4}=\frac{3+\sqrt{10.6}}{-0.8} $
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